Jrue Holiday Agrees To Extend Bucks’ Stay By Four Years

jrue holiday
Jrue Holiday

Jrue Holiday, the guard for Milwaukee Bucks, has agreed to a contract extension of four years, worth $135 million. Including bonuses, the total value of the contract is reportedly about $160 million. The player can opt-out after the third year in the 2024-5 season, as per reports.

The Equation With Jrue Holiday

Holiday stated his intent to remain a Bucks for the rest of his career. The official Twitter account of the Bucks featured Jrue Holiday in a posted video. Holiday continued and expressed his gladness at being able to remain with the team. He looks forward to achieving more, he said.

The latest deal is the most recent step taken by the Bucks to increase their investment in the team’s star trio. The trio comprises Jrue Holiday, Giannis Antetokounmpo who is the reigning two-time MVP, and Khris Middleton who has been an All-Star two times. The Milwaukee Bucks have been in the hunt for a title since the last victory in 1971.

Jon Horst, the general manager of the Bucks, expressed his excitement at the news. He praised Jrue as being among the best guards, an elite defender as well as an offensive player with impact.

Jrue Holiday could have opted out for $26.7 million for the remainder of the current season as per his existing contract. The existing one was a five-year deal worth $126 million when Holiday had signed for the New Orleans Pelicans back in 2017.

With the deal, the total amount invested by the Bucks now stands at $105 million for this year, and $113 million and $120 million for the next two seasons respectively.

The player currently has an average score of 17 points, 1.8 steals, 4.6 rebounds, and 5.4 assists. This is his first year with Milwaukee and he is the second-best player in the NBA when it comes to steals successfully completed per game.

Previous articleMannKind (NASDAQ: MNKD) Expected to Post $16.08M Quarterly Sales
Next articleWhat is a SPAC and how is different from a traditional IPO